Python中计算s中不同子串个数的程序
假设我们有一个字符串s，我们必须找到s的不同非空子串的数量。
因此，如果输入类似于s="abaa"，那么输出将是8，因为子字符串是["a","b","ab","ba","aa","aba","咩”，“啊”]。
示例
让我们看看以下实现以获得更好的理解-
from collections import deque
def solve(s):
trie = {}
n = len(s)
for i in range(n):
curr = trie
for j in range(i, n):
c = s[j]
if c not in curr:
curr[c] = {}
curr = curr[c]
curr["*"] = True
q = deque([trie])
ans = 0
while q:
ans += 1
t = q.popleft()
for c in t:
if c != "*":
q.append(t[c])
return ans - 1
s = "abaa"
print(solve(s))输入
"abaa"输出结果
8