在 Python 中查找方程最大值的程序
假设我们有一个名为points的数组，其中包含二维平面上的坐标点，它们按x值排序，其中points[i]=(x_i,y_i)所以x_i 因此，如果输入类似于points=[[2,4],[3,1],[6,11],[7,-9]]k=1，那么输出将为6，因为前两个点满足条件|xi-xj|<=1现在，如果我们计算方程，我们会得到4+1+|2-3|=6.第三个和第四个点也满足条件并返回值11+-9+|6-7|=3，所以最大值是6。 让我们看下面的实现来更好地理解示例
def solve(points, k):
left, right = 0, 1
max_value = float('-inf')
while right < len(points):
xl, yl = points[left]
xr, yr = points[right]
diff = abs(xr - xl)
if left == right:
right += 1
elif diff <= k:
m = yl + yr + diff
max_value = max(max_value, m)
if yl >= yr - diff:
right += 1
else:
left += 1
else:
left += 1
return max_value
points = [[2,4],[3,1],[6,11],[7,-9]]
k = 1
print(solve(points, k))
输入
[[2,4],[3,1],[6,11],[7,-9]], 1输出结果
6