通过ID ASC从数据库顺序中选择最后3行？
您可以使用子查询。以下是语法-
SELECT * FROM ( SELECT * FROM yourTableName ORDER BY yourIdColumnName DESC LIMIT 3 ) anyAliasName ORDER BY yourIdColumnName;
让我们首先创建一个表-
mysql> create table DemoTable ( ClientId int NOT NULL AUTO_INCREMENT PRIMARY KEY, ClientName varchar(100) ); Query OK, 0 rows affected (0.60 sec)
使用插入命令在表中插入一些记录-
mysql> insert into DemoTable(ClientName) values('Larry');
Query OK, 1 row affected (0.18 sec)
mysql> insert into DemoTable(ClientName) values('Chris');
Query OK, 1 row affected (0.12 sec)
mysql> insert into DemoTable(ClientName) values('Bob');
Query OK, 1 row affected (0.10 sec)
mysql> insert into DemoTable(ClientName) values('David');
Query OK, 1 row affected (0.12 sec)
mysql> insert into DemoTable(ClientName) values('Carol');
Query OK, 1 row affected (0.10 sec)
mysql> insert into DemoTable(ClientName) values('Robert');
Query OK, 1 row affected (0.19 sec)
mysql> insert into DemoTable(ClientName) values('Sam');
Query OK, 1 row affected (0.17 sec)
mysql> insert into DemoTable(ClientName) values('Mike');
Query OK, 1 row affected (0.12 sec)使用select语句显示表中的所有记录-
mysql> select *from DemoTable;
这将产生以下输出-
+----------+------------+ | ClientId | ClientName | +----------+------------+ | 1 | Larry | | 2 | Chris | | 3 | Bob | | 4 | David | | 5 | Carol | | 6 | Robert | | 7 | Sam | | 8 | Mike | +----------+------------+ 8 rows in set (0.00 sec)
以下是通过IDASC从数据库顺序中选择最后3行的查询-
mysql> SELECT * FROM ( SELECT * FROM DemoTable ORDER BY ClientId DESC LIMIT 3 ) tbl ORDER BY ClientId ASC;
这将产生以下输出-
+----------+------------+ | ClientId | ClientName | +----------+------------+ | 6 | Robert | | 7 | Sam | | 8 | Mike | +----------+------------+ 3 rows in set (0.00 sec)