MySQL的两个时间戳之间的差异秒？

2024-05-01 15:35:53 100

您可以使用MySQL的内置函数UNIX_TIMESTAMP()来获取时间戳和两个时间戳之间的差。语法如下-

SELECT UNIX_TIMESTAMP(yourColumnName1) - UNIX_TIMESTAMP(yourColumnName2) as anyVariableName from yourTableName;

为了理解上述概念，让我们创建一个表。以下是创建表的查询-

mysql> create table DifferenceInSeconds
   −> (
   −> FirstTimestamp TIMESTAMP,
   −> SecondTimestamp TIMESTAMP
   −> );

使用insert命令在表中插入一些记录。查询如下-

mysql> insert into DifferenceInSeconds values('2012-12-12 13:16:55','2012-12-12 13:13:55');

mysql> insert into DifferenceInSeconds values('2014-10-11 12:15:50','2014-10-11 12:13:50');

mysql> insert into DifferenceInSeconds values('2018-12-14 13:30:53','2018-12-14 13:27:53');

现在，使用select语句显示表中的所有记录。查询如下-

mysql> select *from DifferenceInSeconds;

以下是输出-

+---------------------+---------------------+
| FirstTimestamp      | SecondTimestamp     |
+---------------------+---------------------+
| 2012-12-12 13:16:55 | 2012-12-12 13:13:55 |
| 2014-10-11 12:15:50 | 2014-10-11 12:13:50 |
| 2018-12-14 13:30:53 | 2018-12-14 13:27:53 |
+---------------------+---------------------+
3 rows in set (0.00 sec)

这是查询，以秒为单位查找两个时间戳之间的时差。查询如下-

mysql> SELECT UNIX_TIMESTAMP(FirstTimestamp) - UNIX_TIMESTAMP(SecondTimestamp) as Seconds from DifferenceInSeconds;

以下是输出-

+---------+
| Seconds |
+---------+
|     180 |
|     120 |
|     180 |
+---------+
3 rows in set (0.00 sec)

注 –如果您不知道哪个时间戳更大，请使用ABS()。

语法如下-

SELECT ABS(UNIX_TIMESTAMP(yourColumnName1) - UNIX_TIMESTAMP(yourColumnName2)) as Seconds from DifferenceInSeconds;

为了检查以上语法，让我们插入第一个时间戳值较低的记录。

mysql> insert into DifferenceInSeconds values('2018-12-14 13:26:53','2018-12-14 13:31:53');

查询以显示表中的所有记录。

mysql> select *from DifferenceInSeconds;

以下是输出-

+---------------------+---------------------+
| FirstTimestamp      | SecondTimestamp     |
+---------------------+---------------------+
| 2012-12-12 13:16:55 | 2012-12-12 13:13:55 |
| 2014-10-11 12:15:50 | 2014-10-11 12:13:50 |
| 2018-12-14 13:30:53 | 2018-12-14 13:27:53 |
| 2018-12-14 13:26:53 | 2018-12-14 13:31:53 |
+---------------------+---------------------+
4 rows in set (0.00 sec)

以下是ABS()方法的使用。查询如下-

mysql> SELECT ABS(UNIX_TIMESTAMP(FirstTimestamp) - UNIX_TIMESTAMP(SecondTimestamp)) as Seconds from DifferenceInSeconds;

以下是输出-

+---------+
| Seconds |
+---------+
|     180 |
|     120 |
|     180 |
|     300 |
+---------+
4 rows in set (0.00 sec)

注意 -如果不使用，ABS()则-300秒将是以上输出。

MySQL的两个时间戳之间的差异秒？

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