在MySQL SELECT中格式化日期*查询uisng FORMATDATE()方法？
使用DATE_FORMAT()，而不是FORMATDATE()在MySQL中格式化日期。正确的语法如下-
SE LECT *, DATE_FORMAT(yourDateCoumnName,’yourFormat’) as anyAliasName FROM yourTableName
为了理解上述语法，让我们创建一个表。创建表的查询如下-
mysql> create table DateFormatDemo -> ( -> Id int NOT NULL AUTO_INCREMENT PRIMARY KEY, -> UserName varchar(10), -> UserLoginDate date -> );
使用insert命令在表中插入一些记录。查询如下-
mysql> insert into DateFormatDemo(UserName,UserLoginDate) values('Mike',curdate());
mysql> insert into DateFormatDemo(UserName,UserLoginDate) values('Sam','2018-05-09');
mysql> insert into DateFormatDemo(UserName,UserLoginDate) values('Carol','2016-01-15');
mysql> insert into DateFormatDemo(UserName,UserLoginDate) values('Bob','2015-12-31');
mysql> insert into DateFormatDemo(UserName,UserLoginDate) values('David','2012-08-19');使用select语句显示表中的所有记录。查询如下-
mysql> select *from DateFormatDemo;
以下是输出-
+----+----------+---------------+ | Id | UserName | UserLoginDate | +----+----------+---------------+ | 1 | Mike | 2019-02-06 | | 2 | Sam | 2018-05-09 | | 3 | Carol | 2016-01-15 | | 4 | Bob | 2015-12-31 | | 5 | David | 2012-08-19 | +----+----------+---------------+ 5 rows in set (0.00 sec)
让我们使用带有SELECT*的DATE_FORMAT()格式化日期。查询如下-
mysql> select *,DATE_FORMAT(UserLoginDate,'%d-%m-%Y') as NewFormatOfDate from DateFormatDemo;
以下是输出-
+----+----------+---------------+-----------------+ | Id | UserName | UserLoginDate | NewFormatOfDate | +----+----------+---------------+-----------------+ | 1 | Mike | 2019-02-06 | 06-02-2019 | | 2 | Sam | 2018-05-09 | 09-05-2018 | | 3 | Carol | 2016-01-15 | 15-01-2016 | | 4 | Bob | 2015-12-31 | 31-12-2015 | | 5 | David | 2012-08-19 | 19-08-2012 | +----+----------+---------------+-----------------+ 5 rows in set (0.00 sec)