C ++中的fmax()和fmin()
在本节中，我们将看到如何转换fmax()和fmin()C++中。的fmax()和fmin()存在于CMATH头文件。
此函数采用float或double或longdouble类型的两个值，fmax()并fmin()分别使用和返回最大值或最小值。
如果参数类型不同，例如有人要比较float和double，或者将longdouble与float进行比较，则函数将类型隐式转换为该值，然后返回相应的值。
示例
#include <cmath>
#include <iomanip>
#include <iostream>
using namespace std;
main() {
double res;
//uses of fmax() res = fmax(50.0, 10.0); //compare for both positive value
cout << fixed << setprecision(4) << "fmax(50.0, 10.0) = " << res << endl;
res = fmax(-50.0, 10.0); //comparison between opposite sign
cout << fixed << setprecision(4) << "fmax(-50.0, 10.0) = " << res << endl;
res = fmax(-50.0, -10.0); //compare when both are negative
cout << fixed << setprecision(4) << "fmax(-50.0, -10.0) = " << res << endl;
//uses of fmin() res = fmin(50.0, 10.0); //compare for both positive value
cout << fixed << setprecision(4) << "fmin(50.0, 10.0) = " << res << endl;
res = fmin(-50.0, 10.0); //comparison between opposite sign
cout << fixed << setprecision(4) << "fmin(-50.0, 10.0) = " << res << endl;
res = fmin(-50.0, -10.0); //compare when both are negative
cout << fixed << setprecision(4) << "fmin(-50.0, -10.0) = " << res << endl;
}输出结果
fmax(50.0, 10.0) = 50.0000 fmax(-50.0, 10.0) = 10.0000 fmax(-50.0, -10.0) = -10.0000 fmin(50.0, 10.0) = 10.0000 fmin(-50.0, 10.0) = -50.0000 fmin(-50.0, -10.0) = -50.0000