C ++程序通过将结构传递给函数来添加复数

2024-05-15 09:52:04 91

复数是表示为a+bi的数字，其中i是虚数，而a和b是实数。一些关于复数的例子是-

2+5i
3-9i
8+2i

通过将结构传递给函数来添加复数的程序如下所示-

示例

#include <iostream>

using namespace std;
typedef struct complexNumber {
   float real;
   float imag;
};
complexNumber addCN(complexNumber num1,complexNumber num2) {
   complexNumber temp;
   temp.real = num1.real + num2.real;
   temp.imag = num1.imag + num2.imag;
   return(temp);
}
int main() {
   complexNumber num1, num2, sum;
   cout << "Enter real part of Complex Number 1: " << endl;

   cin >> num1.real;
   cout << "Enter imaginary part of Complex Number 1: " << endl;

   cin >> num1.imag;
   cout << "Enter real part of Complex Number 2: " << endl;

   cin >> num2.real;
   cout << "Enter imaginary part of Complex Number 2: " << endl;

   cin >> num2.imag;
   sum = addCN(num1, num2);

   if(sum.imag >= 0)
   cout << "Sum of the two complex numbers is "<< sum.real <<" + "<< sum.imag <<"i";
   else
   cout << "Sum of the two complex numbers is "<< sum.real <<" + ("<< sum.imag <<")i";
   return 0;
}

输出结果

上面程序的输出如下-

Enter real part of Complex Number 1: 5
Enter imaginary part of Complex Number 1: -9
Enter real part of Complex Number 2: 3
Enter imaginary part of Complex Number 2: 6
Sum of the two complex numbers is 8 + (-3)i

在上述程序中，结构complexNumber包含复数的实部和虚部。这在下面给出-

struct complexNumber {
   float real;
   float imag;
};

该函数addCN()接受两个类型为complexNumber类型的参数，并将两个数字的实部和虚部相加。然后，将增加的值返回到main()函数。这在下面给出-

complexNumber addCN(complexNumber num1,complexNumber num2) {
   complexNumber temp;
   temp.real = num1.real + num2.real;
   temp.imag = num1.imag + num2.imag;
   return(temp);
}

在该main()方法中，数字的值是从用户那里获得的。这在下面给出-

cout << "Enter real part of Complex Number 1: " << endl;
cin >> num1.real;
cout << "Enter imaginary part of Complex Number 1: " << endl;
cin >> num1.imag;

cout << "Enter real part of Complex Number 2: " << endl;
cin >> num2.real;
cout << "Enter imaginary part of Complex Number 2: " << endl;
cin >> num2.imag;

这两个数字的和是通过调用addCN()函数获得的。然后打印总和。这在下面给出-

sum = addCN(num1, num2);
if(sum.imag >= 0)
cout << "Sum of the two complex numbers is "<< sum.real <<" + "<< sum.imag <<"i";

else
cout << "Sum of the two complex numbers is "<< sum.real <<" + ("<< sum.imag <<")i";

C ++程序通过将结构传递给函数来添加复数

示例

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