Java中的LocalTime compareTo()方法
可以使用compareTo()Java中LocalTime类中的方法比较两个LocalTime对象。此方法需要单个参数，即要比较的LocalTime对象。
如果第一个LocalTime对象大于第二个LocalTime对象，则返回正数；如果第一个LocalTime对象小于第二个LocalTime对象，则返回负数；如果两个LocalTime对象相等，则返回零。
演示此程序如下
示例
import java.time.*;
public class Main{
public static void main(String[] args){
LocalTime lt1 = LocalTime.parse("11:37:12");
LocalTime lt2 = LocalTime.parse("23:15:30");
System.out.println("The first LocalTime object is: " + lt1);
System.out.println("The second LocalTime object is: " + lt2);
int val = lt1.compareTo(lt2);
if(val > 0)
System.out.println("\nThe first LocalTime object is greater than the second LocalTimeobject");
else if(val < 0)
System.out.println("\nThe first LocalTime object is lesser than the second LocalTimeobject");
else
System.out.println("\nThe LocalTime objects are equal");
}
}输出
The first LocalTime object is: 11:37:12 The second LocalTime object is: 23:15:30 The first LocalTime object is lesser than the second LocalTime object
现在让我们了解上面的程序。
首先，显示两个LocalTime对象。然后使用compareTo()方法比较它们，并使用ifelse语句显示结果。演示此代码段如下所示：
LocalTime lt1 = LocalTime.parse("11:37:12");
LocalTime lt2 = LocalTime.parse("23:15:30");
System.out.println("The first LocalTime object is: " + lt1);
System.out.println("The second LocalTime object is: " + lt2);
int val = lt1.compareTo(lt2);
if(val > 0)
System.out.println("\nThe first LocalTime object is greater than the second LocalTimeobject");
else if(val < 0)
System.out.println("\nThe first LocalTime object is lesser than the second LocalTimeobject");
else
System.out.println("\nThe LocalTime objects are equal");