C#中的Math.Max()方法
C#中的Math.Max()方法用于返回两个指定数字中的较大者。此方法适用于Double，Decimal，Int16，Int32等数字。
语法
以下是语法-
public static ulong Max (ulong val1, ulong val2); public static uint Max (uint val1, uint val2); public static ushort Max (ushort val1, ushort val2); public static float Max (float val1, float val2); public static byte Max (byte val1, byte val2); public static long Max (long val1, long val2);
示例
现在让我们看一个实现Math.Max()方法的示例-
using System;
public class Demo {
public static void Main(){
byte val1 = 10, val2 = 15;
decimal val3 = 1000M, val4 = 1500M;
double val5 = 15.896745, val6 = 25.676843;
short val7 = 20, val8 = 30;
Console.WriteLine("Maximum Value from two byte values = "+Math.Max(val1, val2));
Console.WriteLine("Maximum Value from two decimal values = "+Math.Max(val3, val4));
Console.WriteLine("Maximum Value from two double values = "+Math.Max(val5, val6));
Console.WriteLine("Maximum Value from two short values = "+Math.Max(val7, val8));
}
}输出结果
这将产生以下输出-
Maximum Value from two byte values = 15 Maximum Value from two decimal values = 1500 Maximum Value from two double values = 25.676843 Maximum Value from two short values = 30
示例
让我们看另一个实现Math.Max()方法的示例-
using System;
public class Demo {
public static void Main(){
int val1 = 10, val2 = 15;
float val3 = 10.8f, val4 = 25.6f;
Console.WriteLine("Maximum Value from two int values = "+Math.Max(val1, val2));
Console.WriteLine("Maximum Value from two float values = "+Math.Max(val3, val4));
}
}输出结果
这将产生以下输出-
Maximum Value from two int values = 15 Maximum Value from two float values = 25.6