如何在单个MySQL查询中使用GROUP BY，HAVING和ORDER BY显示具有特定范围之和的记录？
让我们首先创建一个表-
mysql> create table DemoTable ( Id int NOT NULL AUTO_INCREMENT PRIMARY KEY, CustomerName varchar(20), ProductPrice int );
使用插入命令在表中插入一些记录-
mysql> insert into DemoTable(CustomerName,ProductPrice) values('Chris',600);
mysql> insert into DemoTable(CustomerName,ProductPrice) values('David',450);
mysql> insert into DemoTable(CustomerName,ProductPrice) values('Chris',980);
mysql> insert into DemoTable(CustomerName,ProductPrice) values('Mike',1200);
mysql> insert into DemoTable(CustomerName,ProductPrice) values('Chris',400);
mysql> insert into DemoTable(CustomerName,ProductPrice) values('David',1200);使用select语句显示表中的所有记录-
mysql> select *from DemoTable;
这将产生以下输出-
+----+--------------+--------------+ | Id | CustomerName | ProductPrice | +----+--------------+--------------+ | 1 | Chris | 600 | | 2 | David | 450 | | 3 | Chris | 980 | | 4 | Mike | 1200 | | 5 | Chris | 400 | | 6 | David | 1200 | +----+--------------+--------------+ 6 rows in set (0.00 sec)
以下是显示特定范围数字的查询-
mysql> select CustomerName,sum(ProductPrice) AS Total_Price from DemoTable group by CustomerName having sum(ProductPrice) between 1600 and 2000 order by CustomerName DESC;
这将产生以下输出-
+--------------+-------------+ | CustomerName | Total_Price | +--------------+-------------+ | David | 1650 | | Chris | 1980 | +--------------+-------------+ 2 rows in set (0.00 sec)