如何在MongoDB对象数组中比较不同对象的属性？
要比较属性，请使用$let和$indexOfArray。首先让我们创建一个包含文档的集合-
> db.demo366.insertOne(
... {
...
... "Name" : "Chris",
... "details" : [
... {
... "Id" : "John1",
... "value" : "test"
... },
... {
... "Id" : "John2",
... "value" : 18
... },
... {
... "Id" : "John3",
... "value" : 20
... }
... ]}
... );
{
"acknowledged" : true,
"insertedId" : ObjectId("5e57ddd92ae06a1609a00ae7")
}在find()方法的帮助下显示集合中的所有文档-
> db.demo366.find();
这将产生以下输出-
{
"_id" : ObjectId("5e57ddd92ae06a1609a00ae7"), "Name" : "Chris", "details" : [
{ "Id" : "John1", "value" : "test" }, { "Id" : "John2", "value" : 18 },
{ "Id" : "John3", "value" : 20 }
]
}以下是查询以比较MongoDB对象数组中不同对象的属性-
> db.demo366.find(
... {"$expr":{
... "$let":{
... "vars":{
... "john2":{"$arrayElemAt":["$details",{"$indexOfArray":["$details.Id","John2"]}]},
... "john3":{"$arrayElemAt":["$details",{"$indexOfArray":["$details.Id","John3"]}]}
... },
... "in":{"$lt":["$$john2.value","$$john3.value"]}}
... }})这将产生以下输出-
{
"_id" : ObjectId("5e57ddd92ae06a1609a00ae7"), "Name" : "Chris", "details" : [
{ "Id" : "John1", "value" : "test" }, { "Id" : "John2", "value" : 18 },
{ "Id" : "John3", "value" : 20 }
]
}