C#中的Type.GetInterfaces()方法
C#中的Type.GetInterfaces()方法用于获取当前Type实现或继承的所有接口。
语法
以下是语法-
public abstract Type[] GetInterfaces ();
示例
现在让我们看一个实现Type.GetInterfaces()方法的示例-
using System;
public class Demo {
public static void Main(){
Type type = typeof(float);
Type myInterface = type.GetInterface("IFormattable",true);
Type[] myInterfaces = type.GetInterfaces();
Console.WriteLine("Interface = "+myInterface);
Console.WriteLine("All the Interfaces...");
for (int i = 0; i < myInterfaces.Length; i++)
Console.WriteLine(""+myInterfaces[i]);
}
}输出结果
这将产生以下输出-
Interface = System.IFormattable All the Interfaces... System.IComparable System.IFormattable System.IConvertible System.IComparable`1[System.Single] System.IEquatable`1[System.Single]
示例
现在让我们来看另一个实现Type.GetInterfaces()方法的示例-
using System;
public class Demo {
public static void Main(){
Type type = typeof(int);
Type myInterface = type.GetInterface("IFormattable");
Type[] myInterfaces = type.GetInterfaces();
Console.WriteLine("Interface = "+myInterface);
Console.WriteLine("All the Interfaces...");
for (int i = 0; i < myInterfaces.Length; i++)
Console.WriteLine(""+myInterfaces[i]);
}
}输出结果
这将产生以下输出-
Interface = System.IFormattable All the Interfaces... System.IComparable System.IFormattable System.IConvertible System.IComparable`1[System.Int32] System.IEquatable`1[System.Int32]