程序检查字符串是否在C中包含任何特殊字符
给定字符串str[]，任务是检查字符串是否包含任何特殊字符，并且如果字符串具有特殊字符，则打印“不接受该字符串”，否则打印“该字符串被接受”。
特殊字符是既不是数字字符也不是字母的字符，即−！@#$％^＆*()+=-\][';/。，{}|::<>？`〜
因此，在C编程语言中，我们将使用if-else方法解决问题。
输入−str[]={“教程点”}
输出-字符串不被接受
输入−str[]={“nhooo”}
输出-字符串被接受
以下使用的方法来解决问题-
遍历整个字符串。
将寻找特殊字符，如果字符串中确实存在特殊字符，则打印“字符串不被接受并中断”。否则，打印字符串被接受。
其他方法
如果我们使用Java或任何其他支持正则表达式概念的语言进行编码，则将使用正则表达式来检查给定字符串中是否存在正则表达式，而不是if-else方法。这不仅是一种简单的方法，而且是一种快速的方法。
算法
Start
In function int special_character(char str[], int n)
Step 1→ initialize i and flag and set flag as 0
Step 2→ Loop For i = 0 and i < n and ++i
If(str[i] == '!' || str[i] == '@' || str[i] == '#' || str[i] == '$'
|| str[i] == '%' || str[i] == '^' || str[i] == '&' || str[i] == '*'
|| str[i] == '(' || str[i] == ')' || str[i] == '-' || str[i] == '{'
|| str[i] == '}' || str[i] == '[' || str[i] == ']' || str[i] == ':'
|| str[i] == ';' || str[i] == '"' || str[i] == '\'' || str[i] == '<'
|| str[i] == '>' || str[i] == '.' || str[i] == '/' || str[i] == '?'
|| str[i] == '~' || str[i] == '`' then
Print "String is not allowed”
Set flag as 1
break
Step 3→ If flag == 0 then,
Print "string is accepted”
In function int main(int argc, char const *argv[])
Step 1→ Declare and set str[] as {"Tutorials-point"}
Step 2→ set n as strlen(str)
Step 3→ special_character(str, n)
Stop示例
#include <stdio.h>
#include <string.h>
int special_character(char str[], int n){
int i, flag = 0;
for (i = 0; i < n; ++i){
//checking each character of the string for special character.
if(str[i] == '!' || str[i] == '@' || str[i] == '#' || str[i] == '$'
|| str[i] == '%' || str[i] == '^' || str[i] == '&' || str[i] == '*'
|| str[i] == '(' || str[i] == ')' || str[i] == '-' || str[i] == '{'
|| str[i] == '}' || str[i] == '[' || str[i] == ']' || str[i] == ':'
|| str[i] == ';' || str[i] == '"' || str[i] == '\'' || str[i] == '<'
|| str[i] == '>' || str[i] == '.' || str[i] == '/' || str[i] == '?'
|| str[i] == '~' || str[i] == '`' ){
printf("String is not allowed\n");
flag = 1;
break;
}
}
//if there is no special charcter
if (flag == 0){
printf("string is accepted\n");
}
return 0;
}
int main(int argc, char const *argv[]){
char str[] = {"Tutorials-point"};
int n = strlen(str);
special_character(str, n);
return 0;
}输出结果
如果运行上面的代码，它将生成以下输出-
String is not allowed