C#程序检查数字是否为正，负，奇，偶，零
检查以下条件-
对于奇数和偶数，请检查数字除以2后的余数-
// checking for odd/ even
if(n % 2 == 0) {
Console.WriteLine("Even");
} else {
Console.WriteLine("Odd");
}对于肯定，否定并检查数字是否为0-
if (n < 0) {
Console.WriteLine("Negative Number!");
} else if(n == 0) {
Console.WriteLine("Zero");
} else {
Console.WriteLine("Positive Number!");
}以下是完整的代码：
示例
using System;
using System.Collections.Generic;
public class Demo {
public static void Main(string[] args) {
int n = 19;
// checking for odd/ even
if (n % 2 == 0) {
Console.WriteLine("Even");
} else {
Console.WriteLine("Odd");
}
// checking for positive, negative or 0
if (n < 0) {
Console.WriteLine("Negative Number!");
} else if (n == 0) {
Console.WriteLine("Zero");
} else {
Console.WriteLine("Positive Number!");
}
}
}输出结果
Odd Positive Number!