Python Pandas - 如何以指定的频率对 DateTimeIndex 执行 ceil 操作
要以指定的频率对DateTimeIndex执行ceil操作，请使用方法。对于频率，请使用freq参数。DateTimeIndex.ceil()
首先，导入所需的库-
import pandas as pd
创建一个日期时间索引，周期为5，频率为S，即秒。时区是澳大利亚/阿德莱德-
datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='40S')显示日期时间索引-
print("DateTimeIndex...\n", datetimeindex)具有指定频率的DateTimeIndex日期的Ceil操作-
print("\nPerforming ceil operation...\n",
datetimeindex.ceil(freq='us'))示例
以下是代码-
import pandas as pd
#DatetimeIndexwithperiod5andfrequencyasSi.e.seconds
#timezoneisAustralia/Adelaide
datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='40S')
#displayDateTimeIndex
print("DateTimeIndex...\n", datetimeindex)
#displayDateTimeIndex frequency
print("DateTimeIndex frequency...\n", datetimeindex.freq)
#CeiloperationonDateTimeIndexdatewithfrequency
print("\nPerforming ceil operation...\n",
datetimeindex.ceil(freq='us'))输出结果这将产生以下代码-
DateTimeIndex... DatetimeIndex(['2021-10-18 07:20:32.261811624+10:30', '2021-10-18 07:21:12.261811624+10:30', '2021-10-18 07:21:52.261811624+10:30', '2021-10-18 07:22:32.261811624+10:30', '2021-10-18 07:23:12.261811624+10:30'], dtype='datetime64[ns, Australia/Adelaide]', freq='40S') DateTimeIndex frequency... <40 * Seconds> Performing ceil operation... DatetimeIndex(['2021-10-18 07:20:32.261812+10:30', '2021-10-18 07:21:12.261812+10:30', '2021-10-18 07:21:52.261812+10:30', '2021-10-18 07:22:32.261812+10:30', '2021-10-18 07:23:12.261812+10:30'], dtype='datetime64[ns, Australia/Adelaide]', freq=None)