Python Pandas - 从 DateTimeIndex 创建一个 DataFrame 但覆盖结果列的名称
要从DateTimeIndex创建DataFrame,请使用.我们已经设置了name参数来覆盖结果列的名称。datetimeindex.to_frame()
首先,导入所需的库-
import pandas as pd
创建一个日期时间索引,周期为5,频率为S,即秒-
datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5, tz='Australia/Adelaide', freq='40S')
显示日期时间索引-
print("DateTimeIndex...\n", datetimeindex)
未使用'False'参数在返回的DataFrame中设置原始索引。为了覆盖结果列的名称,我们使用了'name'参数-
print("\nDateTimeIndex to DataFrame...\n", datetimeindex.to_frame(index=False, name = 'DateTimeData'))
示例
以下是代码-
import pandas as pd #DatetimeIndexwithperiod5andfrequencyasSi.e.seconds #timezoneisAustralia/Adelaide datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5, tz='Australia/Adelaide', freq='40S') #displayDateTimeIndex print("DateTimeIndex...\n", datetimeindex) #displayDateTimeIndex frequency print("\nDateTimeIndex frequency...\n", datetimeindex.freq) #CreateaDataFramefromDateTimeIndex # The original index isn't set in the returned DataFrame using the 'False' parameter # To override the name of the resulting column, we have used the 'name' parameter print("\nDateTimeIndex to DataFrame...\n", datetimeindex.to_frame(index=False, name = 'DateTimeData'))输出结果
这将产生以下代码-
DateTimeIndex... DatetimeIndex(['2021-10-18 07:20:32.261811624+10:30', '2021-10-18 07:21:12.261811624+10:30', '2021-10-18 07:21:52.261811624+10:30', '2021-10-18 07:22:32.261811624+10:30', '2021-10-18 07:23:12.261811624+10:30'], dtype='datetime64[ns, Australia/Adelaide]', freq='40S') DateTimeIndex frequency... <40 * Seconds> DateTimeIndex to DataFrame... DateTimeData 0 2021-10-18 07:20:32.261811624+10:30 1 2021-10-18 07:21:12.261811624+10:30 2 2021-10-18 07:21:52.261811624+10:30 3 2021-10-18 07:22:32.261811624+10:30 4 2021-10-18 07:23:12.261811624+10:30