Python Pandas - 从 TimeDeltaIndex 中提取每个元素的秒数
要从TimeDeltaIndex对象中提取每个元素的秒数，请使用TimedeltaIndex.seconds属性
首先，导入所需的库-
import pandas as pd
创建一个TimeDeltaIndex对象。我们也使用'data'参数设置了类似timedelta的数据-
tdIndex = pd.TimedeltaIndex(data =['10 day 5h 2 min 35s 3us 10ns', '+22:39:19.999999', '2 day 4h 03:08:02.000045', '+21:15:45.999999'])
显示TimedeltaIndex-
print("TimedeltaIndex...\n", tdIndex)显示TimeDeltaIndex的每个元素的秒数-
print("\nThe number of seconds from the TimeDeltaIndex object...\n", tdIndex.seconds)示例
以下是代码-
import pandas as pd
#CreateaTimeDeltaIndexobject
# We have set the timedelta-like data using the 'data' parameter as well
tdIndex = pd.TimedeltaIndex(data =['10 day 5h 2 min 35s 3us 10ns', '+22:39:19.999999',
'2 day 4h 03:08:02.000045', '+21:15:45.999999'])
#displayTimedeltaIndex
print("TimedeltaIndex...\n", tdIndex)
#displaythenumberofsecondsfromeachelementofTimeDeltaIndex
print("\nThe number of seconds from the TimeDeltaIndex object...\n", tdIndex.seconds)
#ReturnadataframeofthecomponentsofTimeDeltas
print("\nThe Dataframe of the components of TimeDeltas...\n", tdIndex.components)输出结果这将产生以下代码-
TimedeltaIndex... TimedeltaIndex(['10 days 05:02:35.000003010', '0 days 22:39:19.999999', '2 days 07:08:02.000045', '0 days 21:15:45.999999'], dtype='timedelta64[ns]', freq=None) The number of seconds from the TimeDeltaIndex object... Int64Index([18155, 81559, 25682, 76545], dtype='int64') The Dataframe of the components of TimeDeltas... days hours minutes seconds milliseconds microseconds nanoseconds 0 10 5 2 35 0 3 10 1 0 22 39 19 999 999 0 2 2 7 8 2 0 45 0 3 0 21 15 45 999 999 0