Python Pandas - 如何以毫秒频率对 DateTimeIndex 执行地板操作
要以毫秒频率对DateTimeIndex执行地板操作，请使用方法。对于毫秒频率，使用值为'ms'的freq参数。DateTimeIndex.floor()
首先，导入所需的库-
import pandas as pd
DatetimeIndex周期为7，频率为S，即秒-
datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='40S')显示日期时间索引-
print("DateTimeIndex...\n", datetimeindex)以毫秒为频率对DateTimeIndex日期进行地板操作。对于毫秒频率，我们使用了'ms'-
print("\nPerforming floor operation with milliseconds frequency...\n",
datetimeindex.floor(freq='ms'))示例
以下是代码-
import pandas as pd
#DatetimeIndexwithperiod7andfrequencyasSi.e.seconds
#timezoneisAustralia/Adelaide
datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='40S')
#displayDateTimeIndex
print("DateTimeIndex...\n", datetimeindex)
#displayDateTimeIndex frequency
print("DateTimeIndex frequency...\n", datetimeindex.freq)
#FlooroperationonDateTimeIndexdatewithmillisecondsfrequency
# For milliseconds frequency, we have used 'ms'
print("\nPerforming floor operation with milliseconds frequency...\n",
datetimeindex.floor(freq='ms'))输出结果这将产生以下代码-
DateTimeIndex... DatetimeIndex(['2021-10-18 07:20:32.261811624+10:30', '2021-10-18 07:21:12.261811624+10:30', '2021-10-18 07:21:52.261811624+10:30', '2021-10-18 07:22:32.261811624+10:30', '2021-10-18 07:23:12.261811624+10:30'], dtype='datetime64[ns, Australia/Adelaide]', freq='40S') DateTimeIndex frequency... <40 * Seconds> Performing floor operation with milliseconds frequency... DatetimeIndex(['2021-10-18 07:20:32.261000+10:30', '2021-10-18 07:21:12.261000+10:30', '2021-10-18 07:21:52.261000+10:30', '2021-10-18 07:22:32.261000+10:30', '2021-10-18 07:23:12.261000+10:30'], dtype='datetime64[ns, Australia/Adelaide]', freq=None)