Python Pandas - 从 TimeDeltaIndex 创建一个系列
使用to_series()方法从Pandas中的TimeDeltaIndex创建一个系列。
首先，导入所需的库-
import pandas as pd
创建一个TimeDeltaIndex对象。我们已经使用'data'参数设置了类似timedelta的数据-
tdIndex = pd.TimedeltaIndex(data =['10 day 5h 2 min 3us 10ns', '+22:39:19.999999', '2 day 4h 03:08:02.000045', '+21:15:45.999999'])
将TimeDeltaIndex转换为系列-
print("\nTimeDeltaIndex to series...\n", tdIndex.to_series())示例
以下是代码-
import pandas as pd
#CreateaTimeDeltaIndexobject
# We have set the timedelta-like data using the 'data' parameter
tdIndex = pd.TimedeltaIndex(data =['10 day 5h 2 min 3us 10ns', '+22:39:19.999999',
'2 day 4h 03:08:02.000045', '+21:15:45.999999'])
#displayTimedeltaIndex
print("TimedeltaIndex...\n", tdIndex)
#ReturnadataframeofthecomponentsofTimeDeltas
print("\nThe Dataframe of the components of TimeDeltas...\n", tdIndex.components)
#ReturnTimeDeltaIndexasobjectndarray
print("\nReturn TimeDeltaIndex as object ndarray ofdatetime.datetimeobjects...\n",
tdIndex.to_pytimedelta())
#ConvertTimeDeltaIndextoSeries
print("\nTimeDeltaIndex to series...\n", tdIndex.to_series())输出结果这将产生以下代码-
TimedeltaIndex... TimedeltaIndex(['10 days 05:02:00.000003010', '0 days 22:39:19.999999', '2 days 07:08:02.000045', '0 days 21:15:45.999999'], dtype='timedelta64[ns]', freq=None) The Dataframe of the components of TimeDeltas... days hours minutes seconds milliseconds microseconds nanoseconds 0 10 5 2 0 0 3 10 1 0 22 39 19 999 999 0 2 2 7 8 2 0 45 0 3 0 21 15 45 999 999 0 Return TimeDeltaIndex as object ndarray ofdatetime.datetimeobjects... [datetime.timedelta(days=10, seconds=18120, microseconds=3) datetime.timedelta(seconds=81559, microseconds=999999) datetime.timedelta(days=2, seconds=25682, microseconds=45) datetime.timedelta(seconds=76545, microseconds=999999)] TimeDeltaIndex to series... 10 days 05:02:00.000003010 10 days 05:02:00.000003010 0 days 22:39:19.999999 0 days 22:39:19.999999 2 days 07:08:02.000045 2 days 07:08:02.000045 0 days 21:15:45.999999 0 days 21:15:45.999999 dtype: timedelta64[ns]