Python Pandas - 从类似数组的元组构造一个 IntervalArray 并返回每个 Interval 的正确端点
要从类似数组的元组构造IntervalArray，请使用pandas.arrays。IntervalArray.from_tuples()方法。要返回IntervalArray中每个Interval的正确端点，请使用array.right属性。
首先，导入所需的库-
import pandas as pd
从类似数组的元组构造一个新的IntervalArray-
array = pd.arrays.IntervalArray.from_tuples([(10, 25),(15, 70)])
显示间隔-
print("Our IntervalArray...\n",array)获得正确的端点-
print("\nThe right endpoints of each Interval in the IntervalArray as an Index...\n", array.right)示例
以下是代码-
import pandas as pd
#从类似数组的元组构造一个新的IntervalArray
array = pd.arrays.IntervalArray.from_tuples([(10, 25),(15, 70)])
#显示间隔数组
print("Our IntervalArray...\n",array)
#获取IntervalArray的长度
#返回一个索引，其中的条目表示IntervalArray中每个Interval的长度
print("\nOur IntervalArray length...\n",array.length)
#IntervalArray中每个Interval的中点作为索引
print("\nThe midpoint of each interval in the IntervalArray...\n",array.mid)
#获得正确的端点
print("\nThe right endpoints of each Interval in the IntervalArray as an Index...\n",array.right)输出结果这将产生以下代码-
Our IntervalArray... <IntervalArray> [(10, 25], (15, 70]] Length: 2, dtype: interval[int64, right] Our IntervalArray length... Int64Index([15, 55], dtype='int64') The midpoint of each interval in the IntervalArray... Float64Index([17.5, 42.5], dtype='float64') The right endpoints of each Interval in the IntervalArray as an Index... Int64Index([25, 70], dtype='int64')