Python Pandas - 从分割数组构造一个 IntervalArray 并返回每个间隔的左端点
要从拆分数组构造IntervalArray，请使用pandas.arrays。IntervalArray.from_breaks().要返回每个间隔的左端点，请使用array.left属性
首先，导入所需的库-
import pandas as pd
从类似数组的拆分构造一个新的IntervalArray-
array = pd.arrays.IntervalArray.from_breaks([0, 1, 2, 3, 4, 5])
显示间隔-
print("Our IntervalArray...\n",array)获取左端点-
print("\nThe left endpoints of each Interval in the IntervalArray as an Index...\n",array.left)示例
以下是代码-
import pandas as pd
#从类似数组的拆分构造一个新的IntervalArray
array = pd.arrays.IntervalArray.from_breaks([0, 1, 2, 3, 4, 5])
#显示间隔数组
print("Our IntervalArray...\n",array)
#获取IntervalArray的长度
#返回一个索引，其中的条目表示IntervalArray中每个Interval的长度
print("\nOur IntervalArray length...\n",array.length)
#IntervalArray中每个Interval的中点作为索引
print("\nThe midpoint of each interval in the IntervalArray...\n",array.mid)
#获取左端点
print("\nThe left endpoints of each Interval in the IntervalArray as an Index...\n",array.left)输出结果这将产生以下代码-
Our IntervalArray... <IntervalArray> [(0, 1], (1, 2], (2, 3], (3, 4], (4, 5]] Length: 5, dtype: interval[int64, right] Our IntervalArray length... Int64Index([1, 1, 1, 1, 1], dtype='int64') The midpoint of each interval in the IntervalArray... Float64Index([0.5, 1.5, 2.5, 3.5, 4.5], dtype='float64') The left endpoints of each Interval in the IntervalArray as an Index... Int64Index([0, 1, 2, 3, 4], dtype='int64')