在Python中查找具有相同首字母单词的最长连续子列表长度的程序
假设我们有一个称为单词的小写字母字符串列表。我们必须找到最长连续子列表的长度,其中每个单词的第一个字母具有相同的第一个字母。
所以,如果输入像words=["she","sells","seashells","on","the","sea","shore"],那么输出将是3,最长的连续子列表是["she","sells","seashells"]。每个单词的第一个字母是“s”。
示例
让我们看下面的实现来更好地理解
def solve(words): cnt = 1 maxcnt = 0 prev_char = "" for word in words: if prev_char == "": prev_char = word[0] elif prev_char == word[0]: cnt += 1 else: prev_char = word[0] cnt = 1 maxcnt = max(maxcnt, cnt) return maxcnt words = ["she", "sells", "seashells", "on", "the", "sea", "shore"] print(solve(words))
输入
["she", "sells", "seashells", "on", "the", "sea", "shore"]输出结果
3