如何在R中的data.table对象列中分隔特定文本和剩余文本？
要将特定文本和data.tableR中对象列中的剩余文本分开，我们可以按照以下步骤操作-
首先，创建一个data.table对象。
然后，使用stringr包中的str_split函数将第一个文本值和剩余文本分开。
示例
创建data.table对象
让我们创建一个data.table对象，如下所示-
library(data.table)
Student_ID<-
sample(c("1Rosy","3Numan","8John","2Shera","9Hina"),25,replace=TRUE)
DT<-data.table(Student_ID)
DT输出结果执行时，上述脚本生成以下内容output(thisoutputwillvaryonyoursystemduetorandomization)-
Student_ID 1: 9Hina 2: 1Rosy 3: 3Numan 4: 9Hina 5: 8John 6: 9Hina 7: 9Hina 8: 1Rosy 9: 3Numan 10: 8John 11: 9Hina 12: 1Rosy 13: 9Hina 14: 8John 15: 1Rosy 16: 2Shera 17: 1Rosy 18: 3Numan 19: 8John 20: 1Rosy 21: 9Hina 22: 8John 23: 8John 24: 8John 25: 9Hina Student_ID
将字符串列中的第一个值和其余文本分开
使用stringr包中的str_split函数将data.table对象DT中Student_ID列的每一行中的第一个文本值和剩余文本分开-
library(data.table)
Student_ID<-
sample(c("1Rosy","3Numan","8John","2Shera","9Hina"),25,replace=TRUE)
DT<-data.table(Student_ID)
library(stringr)
DT$ID_Name<-str_split(DT$Student_ID,"(?<=.{1})",2)
DT输出结果Student_ID ID_Name 1: 9Hina 9, Hina 2: 1Rosy 1, Rosy 3: 3Numan 3, Numan 4: 9Hina 9, Hina 5: 8John 8, John 6: 9Hina 9, Hina 7: 9Hina 9, Hina 8: 1Rosy 1, Rosy 9: 3Numan 3, Numan 10: 8John 8, John 11: 9Hina 9, Hina 12: 1Rosy 1, Rosy 13: 9Hina 9, Hina 14: 8John 8, John 15: 1Rosy 1, Rosy 16: 2Shera 2, Shera 17: 1Rosy 1, Rosy 18: 3Numan 3 ,Numan 19: 8John 8, John 20: 1Rosy 1, Rosy 21: 9Hina 9, Hina 22: 8John 8, John 23: 8John 8, John 24: 8John 8, John 25: 9Hina 9, Hina Student_ID ID_Name